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courses:rg:2012:distributed-perceptron [2012/12/16 15:25] machacek |
courses:rg:2012:distributed-perceptron [2012/12/16 23:44] (current) machacek |
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- | ====== Distributed Training Strategies for the Structured Perceptron - RG report ====== | + | ====== Distributed Training Strategies for the Structured Perceptron - RG report |
+ | |||
+ | ===== Presentation ===== | ||
+ | |||
+ | ==== 3 Structured Perceptron ==== | ||
+ | |||
+ | * In unstructured perceptron, you are trying to separate two sets of with hyperplane. See Question 1 for the algorithm. In training phase, you iterate your training data and adjust the hyperplane every time you make a mistake. [[http:// | ||
+ | |||
+ | * Structured (or multiclass) perceptron is generalization of the unstructured perceptron. See figure 1 in the paper for the algorithm. | ||
+ | * You can use any structured input x (not just vector, sentence for example) and any structured output y (not just binary value, parse tree for example) | ||
+ | * You need to have fuction f(x,y) which returns feature representation of candidate input-output pair | ||
+ | * Using the Theorem 1, you can bound the number of mistakes made during the training | ||
+ | * The computational time is therefore also bounded. | ||
+ | * This holds only for linearly separable sets. | ||
+ | * Other remarks and discussed issues | ||
+ | * The perceptron training algorithm does not always return the same weights (unlike maximal margin). It depends on order of training data. | ||
+ | * How the inference is done in the difficult tasks like parsing? Iterating all possible y? Approximation? | ||
+ | |||
+ | ==== 4 Distributed Structured Perceptron ==== | ||
+ | |||
+ | * Motivation: There is no straightforward way to make the standard perceptron algorithm parallel. | ||
+ | |||
+ | === 4.1 Parameter Mixing === | ||
+ | |||
+ | * First attempt to map-reduce algorithm | ||
+ | * Divide the training data into shards | ||
+ | * In MAP step, train a perceptron on each shard | ||
+ | * In REDUCE step, average the trained weight vectors | ||
+ | |||
+ | === 4.2 Iterative Parameter Mixing === | ||
+ | |||
+ | ==== 5 Experiments ==== | ||
+ | |||
===== Questions ===== | ===== Questions ===== | ||
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return w(k) | return w(k) | ||
- | Let us set learning_rate=0.3, | + | |
+ | |||
+ | Let us set learning_rate | ||
X = [(1, 0), (0, 1)] // data | X = [(1, 0), (0, 1)] // data | ||
Y = [0, 1] // classes | Y = [0, 1] // classes | ||
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w = [?, ?] | w = [?, ?] | ||
+ | |||
+ | **Answer:** | ||
+ | |||
+ | | x_1 | x_2 | y | w_1 | w_2 | x \dot w | y' | e = y - y' | Δw_1 = α * e * x_1 | Δw_2 = α * e * x_2 | | ||
+ | |1|0|0|0|0|0|0|0|0|0| | ||
+ | |0|1|1|0|0|0|0|1|0|0.3| | ||
+ | |1|0|0|0|0.3|0|0|0|0|0| | ||
+ | |0|1|1|0|0.3|0.3|0|1|0|0.3| | ||
+ | |1|0|0|0|0.6|0|0|0|0|0| | ||
+ | |0|1|1|0|0.6|0.6|1|0|0|0| | ||
+ | |||
+ | w = [0, 0.6] | ||
+ | |||
+ | | ||
==== Question 2 ==== | ==== Question 2 ==== | ||
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f = ? | f = ? | ||
w = [?, ?] | w = [?, ?] | ||
+ | |||
+ | **Answer 1:** | ||
+ | |||
+ | f(**x**,y) = (y == 0) ? (**x**, 0,0,...,0) : (0, | ||
+ | |||
+ | **Answer 2:** | ||
+ | |||
+ | Acording to English [[http:// | ||
+ | |||
+ | However, I would say, that this holds only for activation treshold = 0. Therefore, this formula cannot be used to compute example from Question 1. | ||
+ | |||
==== Question 3 ==== | ==== Question 3 ==== | ||
In figure 4, why do you think that the F-measure for Regular Perceptron (first column) learned by the Serial (All Data) algorithm is worse than the Parallel (Iterative Parametere Mix)? | In figure 4, why do you think that the F-measure for Regular Perceptron (first column) learned by the Serial (All Data) algorithm is worse than the Parallel (Iterative Parametere Mix)? | ||
+ | |||
+ | |||
+ | **Answer:** | ||
+ | |||
+ | * Iterative Parameter Mixing is just a form of parameter averaging, which has the same effect as the averaged perceptron. | ||
+ | * F-measures for seral (All Data) and Paralel (Iterative Parameter Mix) are very similar in the second column. It is because the both methods are already averaged. | ||
+ | * Bagging like effect | ||
==== Question 4 ==== | ==== Question 4 ==== | ||
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N = argmax_N f(N, T, F, ...) | N = argmax_N f(N, T, F, ...) | ||
f = ? | f = ? | ||
+ | |||
+ | **Answer:** | ||
+ | |||
+ | We have not concluded on a particular formula. | ||
+ | * It also depends on convergence criteria. | ||
+ | * With no time limitation, the serial algorithm would have the least energy consumption. | ||
+ | * With time limitation, we should use as least shards to meet the time limitation. |